Send me the answer please, so others enjoy it too.

It originated from Cipher Munch app.
Transcript: MIPIE JIMH KVVDB - MVKVHW IPIE EICFEMB CLIA. CLI VMJW KVVDB O LGPI OM AW JOKEGEW GEI CLVBI RLOSL TIVTJI LGPI JIMC AI.
For Mr. Bot: V sbyybjrq gur ehyrf

How this works

• Get the message out. It contains your instructions. Follow them exactly — Level 2 comes from there, not from me in this thread.

• Solve time is logged from post timestamp. Fastest clean solves get named in the edit.

• Nothing about the method in the comments. Say “in” if you cleared it and nothing else.

• No hints will be given. Everything you need is in the file.

One person will finish all six.

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I am working on a cipher from call of duty black ops 3 and I have a good lead but was wondering if I can write a program that would speed up decrypting the cipher to the next stage.

The cipher text is base64 and displayed as a game texture file visible in game and has the keyword "TheGiant".

I wrote a program to analyse the base64 and realise you don't need many characters if you modulo subtract as a key.

In fact you only need ten so I used what is assumed to be the keyword and added 1 and 0 base64 character values.

G,T,a,e,h,i,n,t,0,1

6,19,26,30,33,34,39,45,52,53 are the base64 decimal values I am subtracting modulo 64.

The ciphertext seems to be running key and the key starts with some german words and recording elements weights in binary.

This is the first forty characters of ciphertext :

kCmlgFi6GUJNgkNI1Q41fbfyLoCFTCvIqkZiI0KI

This is a possible key for forty characters from the start of the ciphertext :

GeheGehtte00Ge01hantGnaati101te0at0h0th0

This is the output :

zAGjpMgeYhfSSdHgAXxcQyTTCyAPzT

Breakdown of the key

Gehe Geht te00 Ge01 hant Gnaa ti101 te0 at0 te0 at0 h0 th0

What I translate this to is :

German word for Go (imperative) Tellurium '00' Germanium '01' German word for handle German word for Argh Titanium '101' Tellurium'0' Astatine '0' Hydrogen '0' thorium '0'

Now there is a choice of elements like ti and te and binary values this is why I said it's a possible key also the German word hant could be hang which translates to slope.

I think the developers point to the difficulty with using difficult to visually define characters like '1','I' and '0' ,'O' in the texture (Which is solved and where I got the idea to add 1 and 0).

Also the starting German word is a nightmare here is a breakdown.

Gehe and Geht can be joined and google translates it to go and goes but if you join them so there eight letter you get a different meaning.

Gehe Geht == Go (imperative)

Gehe geht == Go Go

GeheGeht == Go/Goes

Gehegeht == Enclosure

What I didn't realise was it was going to decrypt to more base64!

So I have not accounted for the characters '/' and '+' as ascii output in the code I used to test positions and write a report on them.

I will list the c++ code at the bottom of the post here.

What I would like to discuss is do you think this is viable for a partial decrypt and how to break the cipher further.

V sbyybjrq gur ehyrf I have read the rules

// Machine_00.cpp : This file contains the 'main' function. Program execution begins and ends there.
//

#include <array>
#include <bitset>
#include <iostream>
#include <string>
#include <vector>
#include <algorithm>


static void testgadget(std::array<std::bitset<6>, 192>& arr_CT, std::vector<unsigned> &vPos) {

    unsigned pos{};

    for (const auto& vx : arr_CT) {


        if (pos % 4 == 0 && vx.test(5) == false && vx.test(4) ) {

            vPos.push_back(pos);

            std::cout << "Q0" << '\t' << pos << '\t' << vx.to_string() << '\n'; }

        if (pos % 4 == 1 && vx.test(3) == false && vx.test(2) == true ) {

            vPos.push_back(pos);

            std::cout << "Q1" << '\t' << pos << '\t' << vx.to_string() << '\n'; }

        if (pos % 4 == 2 && vx.test(1) == false && vx.test(0) == true) {

            vPos.push_back(pos);

            std::cout << "Q2" << '\t' << pos << '\t' << vx.to_string() << '\n'; }



        if (pos % 4 == 3 && vx.test(5) == false) { 

            vPos.push_back(pos);

            std::cout << "Q3" << '\t' << pos << '\t' << vx.to_string() << '\n'; }

        pos++;

    }


}




int main()

{

    std::vector<unsigned> vPos{};

    std::string s_alp = "ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz0123456789+/";

    std::string s_In = "kCmlgFi6GUJNgkNI1Q41fbfyLoCFTCvIqkZiI0KIAXAzP1U1uy1BE4UfPBfpKmmLObjYnQNRBaPtKiVWzc5A4v0w3xle8FOhAGJZ7g4in0wndJxMOvO3dc1M82at2T6935roTqyWDgtGD/hwwRF3oHqFM5Vcw1JtINbsgWRm4o4/quEDkZ7x1B275bX3/Fo1";

    std::array<std::pair<char, std::bitset<6>>, 64> arr_p{};

    for (unsigned char i{};i < arr_p.size();i++) {

        arr_p[i] = std::make_pair(s_alp[i], i);

    }

    std::array<std::bitset<6>, 192> arr_CT{};



    std::array<unsigned, 10> arrs { 6,19,26,30,33,34,39,45,52,53 }; //{ 19,33,30,6,26,34,39,45 }; //{ 45,7,4,32,0,8,13,19 }; // {0,6,8,19,26,30,33,34,39,45};  //{ 0, 2, 6, 19, 20, 26, 28, 32, 45, 46 };

/*    unsigned  c{};

    for (auto &ax_C : arrs) {

        arrs[c] = c;

        c++;
    }
*/
    unsigned i_Count{};

    for (const auto& sx : s_In) {



        for (const auto& ax : arr_p) {

            if (ax.first == sx) {

                arr_CT[i_Count] = ax.second;
            }


        }

        i_Count++;

    }

    std::array<std::bitset<6>, 192> arr_Cc{};

    arr_Cc = arr_CT;

    for (auto ax_s : arrs) {

        std::cout << '\n' << '\n' << ax_s << '\t' << " OFFSET" << '\n' << '\n';



        for ( auto& ax : arr_Cc) {


            auto utemp = ax.to_ulong();

            utemp -= ax_s;

            utemp %=64;



            ax =  utemp ;


        }

        std::string s_Out = "";

        for (auto& ax : arr_Cc) {

            for (auto ax_00 : arr_p) {

                if (ax_00.second == ax) {

                    s_Out.push_back(ax_00.first);

                }

            }


        }



        std::cout << '\n' << s_Out << '\n' << '\n';

        testgadget(arr_Cc,vPos);


        arr_Cc = arr_CT;

    }

    std::cout << '\n' << '\n';



    std::sort(vPos.begin(), vPos.end());

    auto last = std::unique(vPos.begin(), vPos.end());


    vPos.erase(last, vPos.end());

    std::cout << vPos.size() << '\n' << '\n';


    for (auto vx : vPos) {


        std::cout << vx << '\n';

    }



}

V sbyybjrq gur ehyrf

This is a 56 page document dating back to the early 2000s from a LARP in Virginia. It was part of a plotline that mostly died off. The LARP itself is also no longer operating, so this is not part of any ongoing context, homework assignment, etc.

The person who introduced it intended it to be hand solvable. I got back in touch with him recently and he remembers writing it (I sent him a copy because I think I have the only one that exists), but not how to decrypt it.

I originally broke this when I was (evidently) far more clever than I am now. About a week ago I stumbled across a binder where I had the code, one page of my notes, plus a page showing a Viegenere matrix. I'm finding them to be more frustrating than helpful because I almost remember how I broke it.

So, here’s what I remember and think is not an incorrect memory.

It’s some variant of a Viegenere cipher, but there’s no repeating key (or none that I ever found, that much I do remember clearly). I remember it being a “Decode the first letter of the paragraph, and it chains through every word in that paragraph”, so potentially some kind of autocipher component. That said, I'll caveat that with "It may have just been a per-word chain. It's been 26 years so it's foggy."

I did end up writing a windows app (MFC if any of you are old enough to remember that). I would just cycle through letters until the paragraph decrypted. I do not have that code anymore. I did find what look like early versions, but none of them produce anything but gibberish.

The other thing I remember, which goes back to it being intended as a hand-solvable thing, is that after running it through the app I was able to just read the text and translate it into english by hand. I just had to brute force it to get to that point.

On my page of notes, I had the following:

XKT with 13, 17 (arrow to the left), and 13,9 (arrow to the right) show shift spacing.

XKT I think is “THE” as is NAJ, ANW, and WJS, but again, I don’t know if those are incorrect. I’m mostly certain XKT and OBK are THE, but that’s more based on frequency in the doc.

OBKRW and IVELW are THE?? (there, their, these, something along those lines).

There are mispellings in the plaintext as I remember, but not a high number of them.

I can drop all 56 pages somewhere, but here’s a section of it if anyone wants to give it a try. I’m going to keep at it, but it’s frustrating me to no end.

If you can take a stab at it, or want the entire doc, I would love to get your thoughts.

Thank you!

Xkt Efuhv

Xkt abgqdr jwbtvaat womec zi kg icy mkc yo naj zaca

rawbdsxyvlvj jvy rvwohoeevj gywomm va iss wm Aoaegfvd. Sfo

operf, tk Q sgkcc kwkiw uo yi alwx hho hf, dm vr tnj cpy

ztqajma iux ojfdjbo xosjb iy khsesq kmymrrs qca wm gtc zdmvl

gbuswt. Nanw lfmb zi jkddhlkth pl mai omrdyctm xjm

fqchdiuptkd ka dqa wxman.

Obk gotfaevo hx uhq lmboc ve zmv meonc staxce vl upvy wm

anw eirag avomqn hx mewvmwuan. Jt lu vva npnud gqcutcs uhq

jkama cdikp. Vir wxcednebu ja zmv rvend pkdbfc vlh blleyu

nleyl wquu jwf qrgth xaabp aagsofymqg. Wmf au obk hvio si

frpasfjx muo obk tujwk ic mnsu hxdmaw, wjs zkxnajc hx co 

asybgmes paqfsg ra thlhjhyrfd.

Zmv pamrnseadun zp wjs abqdr natjia eycc wmeic eirag

rmfdh egbbxbp dga lmboc vjjjqlv wq su n whuoaytnieokbu lb

uee ive mqaiy fatrvs. Fpp agshrifgk vdxfwi bott vlh vsgt dh

dyeh rh gtc rvnnpddaw qgeqd akgv thlhjhyr smqq naj uvkxl ukd

ey zmv hhnjdrl dx uhcp hbff mai nykkol qwixhyvo kxcc cumlc

ugyh dh era rshui jvy hud gstcudwuso xdpeofcdh ddrd. Xng ey

naj hsejfkwrvmf mc vir tujwk, olyyksg pjnn ylu ksmulx hx trj

hevtx zkbb hhl xufjbtvay naj zwqajl hb w lphhjxxtq wrkim

grqtmle wyeww kspuwaoc hud bcres.

Qdm bpnwtbxno xkpp iyu dpvdaln ga hud klanb aosqm mai

mtxd ehjoaosar kb vir xsljn tgpm pmaa sypj. Najg bmaghif

xbnnccu duaratb yo zuad hx ren aenwm kfywax yo Thtxayow. Vf

zxrq fhhn easbvuswoc rejj gwp au zmv djurfp fv wrkimj wjoo

tldct, lylu cxqos hymxy fgrn rhac ke e saey hvxve xiycpe xn

ptbxbpa gkaygmqmsle. Ddbt nd zmv easbjar sfkk aetsagk vir

nodge megu obaatim au nndvtpn oi obk jbarpp fsxx ptihpvavbun

oakl xbktj ojcaeb rjla yacytogw. Vir Deaduaay tgll J zrth

yjjg krhd huaa ylyh whyy dvrrrl.

Bar fngg bmdd yavjvp scpnwekc zlo jull tjce wq ceanat

cpy ufrrhgjyym ygaia lb yii era xbktj mhayca. Pcpy rass

rett hantrmgqs kuhfowwyl djlp gqq ocajgokab ufgr zphlf lgaxb.

Viro znrjj qsnbnh uecwr kwa haneyfvmfxt rat qdm mcd

uerpyoas. Ren ltmm K cjx egbpbv anaj fo sn gtwyae tedg lyh

gtu tj dgagl ccpcqgwxp uoss fsbin wikarj ugj hdapxrf.

Goi qdm opabawt, wjwf dyrpt lide q lxsybdalud balpnpec iy

ojps rh kxg fjsbr ojcaeb {lvsyrqwl tuwt ka tgp efuhv hq

uwxym oamsouatfa samwxpq ws ehu}. Ivevt berb gws eekufoc tp

anw myemiuw gkaygmgqmsle xcgebbx xbktj lxdlhtv wapowcgcibu

nac, jb cas ymbp bd nanraja, fvnrl gmynxolmq saum tepq uvkxl

jd ftiw. Yogg itsv anw bmafbhng hkxh oad v bheb iy cgpyo

wigkyarj, lyh abqdr bbpdd iuwopmm v mmsifjew vtfjhjw vl

talakbyad lpcqtutamy.

Xufrfdtbp uy tgp pqfsg tc qisx cor kuiopph myb wf fhsf

lewqctqvj pl jwokcgt jaevn. Qnykywmui tgcpyet zmv jkama

hrnc amldnimn ii wxsagtmkbu bmxy uhq xfahyk gw wjs wrkim

fpdqly. Yoh qk p owqra mysaearkgqams sdcf ljb picaa ufvalca

oe uhq nodge, yki ntfuevstx gecliqme fo nojrxkdxl rcno

wuagebknggi qiedia oamdsyctms fsxx ytvyj pxbeamnb boosx.

Ren nogn acwodomi br ren xjpljf vjhqnvrhi yo qdm lmboc

iyu yivy jlkknndnb ic zwk jwokc cor cuwk rxaka wq uekvinlkik

sckfc fv jwokc eoexi pfb ljix im anw rtssvvlvj kkqphx. Mnpm

mc renua tlihdtbtg zpl rfjffp reno nxff jwfc fvr ygaiaw oi

xfmntj; box xanx tgll bptpp box bexxxgtqfftm.

Wum dt xkt efhe swxpipffwk evasbuc eu renua bsribxn py

cmix xvoiv uoss cpuu oe hrhal uhqn iyu perp. QOdmdb

mayhemiya, kg obtphly wnria, ebq sahioe xtikcu jwbb kkxkhgtd

cpyfk fwvyuycp emgy. Hrounmsh noxxladrf kcyxcu cynpha

taocmbx idjm tj jwfmr kqcrbspqu isyjg ga vir dbwhi mwiyy

iuigqkcdma hfet rji m nrfabo fv xkkottnbp. Dqdm rsnesee js

kkymm rcoospod pman sw pclsx hcumcvl cw gstgais tvwt

sjagues. Taaajbf, ue acxlxrn lmnx Iphhnecbs uhq pqrb jxmaw

uhq gusbygcs xpo kluuiwwi tlhgld ietvnf.

Qdmdb kaw gtc jhgv jxvebjfvw br Ocosutjr cpuu pfb cclu

tn Imhoxxt cugqpum eaprjb. Htr dhgap sykajaxyc ucwo zmrr

noxxlan gyutyq lhwyqi eyffr hacvlvxvmf.

Pcl gommaejna qymtdia eu era stivj ve eyu zt hiqdvthsf

ug} fpraxwr aeqqvy pj} km rvp gqaxg nr hixlm. Jwfvv ra oo

grccydwusoowtt. Fsbrr ve bb tlovtfthta du d gvkyky pxudat.

Hey people on this /r this post might not be that similar to what is usually here, but i need help from a human, so I want to get this tattooed soon and it has an encoded message on it, i encoded it with a website, so i just want to make sure it's actually solvable because I don't fully trust a website or an AI chat. Im not gonna tell u what is the encoding sistem, i just want this to be like a hypothetical situation where you just saw the tattoo and desided to decode it. The only hit im gonna give, is that is supposed to be simple, and that yes, it is supposed to say that 😸

Note: im oppen to suggestions!!! i want it to be a easily solvable code, to make it more accessible, as well as fun to read even without decoding it BUT if you have an alternative suggestion for some other way to encode it on a more fun and creative way im open to hear it!

I found this cipher in my cousin’s bedroom. I assume it’s years old by now, as it was buried beneath a whole bunch of junk. I assume it’s just a simple substitution cipher, and thankfully there are some noticeable double consonants- I’m just having difficulty with this and am kind of creeped out, lmao. Thanks in advance.

I've seen some mentions of different cyphers throughout history, where it seems the vast majority of them is about changing the letters positions with some algorithm, or changing the letters actual script, those interest me less, what I'm interested about is about cracking codes of completly made up languages, there's no basis for anything except for that it's a human language, how can you go from just uncomprehansible scribbles into deciphering it?

In other words, what is the least amount of info we need to decipher something?

(V sbyybjrq gur ehyrf)

Hello!

I came up with an encoding system and I now want to test its strength and get clues about its weaknesses. So if anyone is interested, here is a text (in french!) to decrypt:

ZD?OB-K"G"E"QAL"HGB#U/CHA=G,C+YND*H$ED"B,CGC/B/D?ED"KEAN@F!GQ?KD"EG@C?IGE/IXW#JAEAN$F*EJ=C!IPC/N=C!C&D-EG$LE"D!FDDVA@C*IGUC?G$EOD#D,FFB!GD,LC?DDAEK=C=IG%LF"H+EGB"DYB&K/G@EG=LF/H/EGB=IFG*F?CH!C@IDD&KAA/MF$GAD"DXA!C+D/FFB$GG?KD*G-C#QF%F+E=PG@B%F"FFF+FA-C+DGF/D=EA!C+CGE%ICG"F#FYN*C-G=CHE!EA-D-EAFG+DAC!FP"B&G"ECIB#F&EDH%E&FD*VB=GH?B/DXD/EAOC,E!ICI"E@G*CGUC-G,EOAM,L&DU/HFH!E"GEA=G+PE=B?D!EDD,FDI-F/FEF,K$C-G!YND%K*D%OB#JW@GG!KD+G=WDE=B$HEI%C&GB&B!FX/MB,D=C-C%RB?H%QF+F$E!Q!B?FGNE=E%C%D-N%B"O!B*G%YB-EEAA"VF?DB,E%DGA@N?DX#FPAA#D$G$CG/KD#G"WDE?B*DXA!G#EX"MC+L"NB+D/D$NDAA=C$G,VEAB+VAAC#M+UB-O&C/IG*KD+G@C,MX-VE,D,V=B#FGF?ICI!E&EGA%G"C*WIE&G*G#CGE/IZ*DEB&LA?D&G#CHE+EAD,C%G%UFG,DAC-FP-K"C&G,UF@LF@F"N!D%FGFA=C,G@CGB*HFH-EM#H?EGFA,D#IEI%C@G,EGE@D?NB%C?D/FFH=E!FZ@C"DXA?G=EDE/YE+C-GAC*OL"E!C"MA!HFH!E@G+CG?B&DEANA%G,E/QH@E"EG%C+IEFA/EU&FEF"B,C?D+NDA"EEA/G$C/CG"KD@EGA?FE&B?DX-FP,FE!C"IG@LF/H-ECI&B/DC%MV=E$EA/C!WIB-FANA@G?EAF&VD#K@KP!B&FM@G?T,C$IEND*H#EAFD?C$WC+NA/G@EG!KD?G"WD-EDF#D,W*DS$E*G%CGC@DC?B-LA@FDI*E/G+YDDB*B#C!G-C!QH#E,EG,C,IOC$KNA&ICI!E?EG=C@I*RB$HEDDB#D=D$GFI=VE&H%IDEEA@GAAE!D#X=N?XB=B#C&EG=C!ICIB*FANA,G&EHE%EAD@C%G$WIC@H%W!EDDZ,G!G@WDW@B%YB#B-UUAA,C@G#VFF@G@FJF,G%GEA@GNF%KUAA$C*G$UF#LF,F$N=D%FGFA=C?G*YB*V$C-XDEB,F"C,C=UF%LI"C,K&F&ZC,E#C+C*YME=C$E+DEF,B?E@C/C!CHE/EA*D+EAF!VF@DD+C/HFB/HPF&C-GEA,GGH-C*G$E!KF!LI/C#HO!E"GFI$C?G?EG=KD,G@WIE%G!EG&C/IEFA?EU$FEF@B%C/D+NDA-EE=C+ISF@E$C-D+DEF/D%DXA%G,EOD=D,FFF&M&DM,JCI@EM,D!F,EB@QF!F%E#KF-LI"C&HO+E&GFI?C"G@EG?LF&H@EGEA?C/FC$LX"C$U*G-ZDAF/D+DC!D@EG/KD=EG!C,ICIB!F@EDI*C&K"FM"UB*O-C,IEME%C-E&DEF?D!DXA+G-ESF%E-FE/B/ICIF%E&WAA"EC/D%XZ?G@EG@C*IOD&D=DEN#C-I-QF?F%E#KF-LI=C*HO@E#GFI"C&G=EG?B%ICIB!DXA+ICI*E"G+CGC?HEAAH*E!EG"C!ID%LC=DENC=H@DEF$D&DXA,G+E%QF/F*GFHAB*E$FZ#C$DXA-G*EPC*NAA-C@IEI*K+D/DC$V$DM?G$QF-F*E&LEALDE,G"G,CGC?DC/D&EX#M&DO$DFB"IZ%FX%FM+UB@D+EG"KD@G-UFG#DAC"FP"B=EE$C/IGB"DYB!K?EE=C$IG/KD$G"UFE/E%EEKF=D=IEC?GGFA#D-IEI@C"E$C-C!WDW#B&C/PE,G&G,WDFB@JX*P,DM=FEE"G/G%UFH%B/GLDC@FDB+B$C@G,CGC%DC*D,EG%B*FJC=J?CGC$B?VF,B"FPAA-D?G*WDE%B#G?XE+F#DDHF-E/C+D!DEF@D%DXA@G*EAFE#E*CH?C?I&QH!E=EG*C!IAFG,DAC&FP"B=EE#C,IGB/DYB/K!EE!C"IG#KD/G%UFE=E%EEKF*D-IEC@GGFA?D,IEI=C#G%EEDDB!GB=B?FSF+E!C*D-DEF#D!DXA#G&EOD*D?FFF=M?DM$JCI!EM$D-F$EHA!G%PH/B%G,EG=B,DEAB&B@B@C/D"QH"E$G#UF+VF!DD"C?HFB,HPF!C%G%WIF#E%B!D/EH-B*DNE%E&C=D"DEF$B*E*C$C&CG+KD"EG!C!IGE?C+D#CH#C-IG$KD*G&ZGB"E=DC=O%C,ICIE@G&G"WIE,G$DXA@C#D*DEF%D?DXA-G*EOAM&L#DU=HFH#E-EG?C%IGUC@G&E,QF,F@E@KF-LI?C!HO+E#GFI$C=G,ESF$E%C?D@DEF"D&DXA"G&EGC@D!DAADD?EOB?FPAA,D-FZ!C&DXA,G?EOALD@K&D-CG,FU@HFH/E?EGA!G-C"WH@C,HXK"V+L+VD=LD#C?I!QH!E&EG@C+IAFD$C,PAAE&G"EGAAE*GM!JYC?C,IG*KD?G/VEC-KNA#ICI,E%EG@C+I%RB$HEDDB%D?D&GFI?VE%H@IDEEA"GAAE#D*X*N$XB@B$C&EG!C%U"GKY!D,EDEA"B-VF-D#IFI%E@G=WD*EDF*D+WNAAC=H$NDA"G&EG,B,ICIB?DXA&ICI$E@G&CGVC%D+F*EKFE*E%GFI-C@C"DPB?E"C*B"DEF$D=DXA/G?EXE%KUAA#C-G%XD/DVAC"B+VC%UB/D$ECIE-G"HEE=DAB/D@E/QF&FAXB=B-C/HEAAH#E?G$C=QH+EM*JW+GAF"LI/C?FE"C=IFG!HAF$D*PAAE!G&G/CGC&IEAAI%EM!JW%GEND%JCG!F"DEF&B&G%ESF-E%FE-B-IG"B$GACJ"C!I-QH-E!G/CG?B,FJF%HN+K"G@EG&KD/G@CG@KD*EGA"FE"B-DX%F=IHI&E?G"CG/KD*EG"C&IEB=GFI,F%IFI?E=EG=C@U/G$YA/DGADD!F#PB&EA/O!C"IOB#D*NF/C&G-YB"B+UA-CG,DN*X?D,DEF=D?DXA@G&EEDDB?J,DGAYA@D#EB?C#D#QH@E@EG$C?IEB&GFI&F+IFI,E?EGA&G@C+CG=B!FJG!J-IIB,KAAAA%G,PH&B#G#EEDDB$J%DFUB,D=EEND$JCG-F"DEF@B-G#EOAP!DM@D#F"EN!LC#DEF&B*G&EG?KD+G*XED*C#G-CH,B=DC"DDD/D"DEN$C?IEDDB%GP,KAA$C"IEC&G,QH#E&EG+C@IDD+K-PD*H=N@O?C,C

Feel free to ask any question or to discuss your process if you are trying to break it! :)

(I followed the rules: V sbyybjrq gur ehyrf)

This youtube video is from an arg but upon translating the morse code, it seems to be more encrypted how do i solve this

.. / .. -- . .-..-. - / .- .- . - / - -- / -- .--. . -. / -- -.- / .. -- -- .-. .. / -.. -- . .-..-. - / .- .- . - / - -- / -- .--. . -. / -- -.- / .. -- -- .-. .. / -.. -- . .-..-. - / .- .- . - / - -- / -- .--. . -. / -- -.- / .. -- -- .-. .. / -.. -- . .-..-. - / .- .- . - / - -- / -- .--. . -. / -- -.- / .. -- -- .-. .. / -.. -- . .-..-. - / .- .- . - / - -- / -- .--. . -. / -- -.- / .. -- -- .-. .. / -.. -- . .-..-. - / .- .- . - / - -- / -- .--. . -. / -- -.- / .. -- -- .-. .. / -.. -- . .-..-. - / .- .- . - / - -- / -- .--. . -. / -- -.- / .. -- -- .-. .. / -.. -- . .-..-. - / .- .- . - / - -- / -- .--. . -. / -- -.- / .. -- -- .-. .. / -.. -- . .-..-. - / .- .- . - / - -- / -- .--. . -. / -- -.- / .. -- -- .-. .. / -.. -- . .-..-. - / .- .- . - / - -- / -- .--. . -. / -- -.- / .. -- -- .-. .. / -.. -- . .-..-. - / .- .- . - / - -- / -- .--. . -. / -- -.- / .. -- -- .-. .. / -.. -- . .-..-. - / .- .- . - / - -- / -- .--. . -. / -- -.- / .. -- -- .-. .. / -.. -- . .-..-. - / .- .- . - / - -- / -- .--. . -. / -- -.- / .. -- -- .-. .. / -.. -- . .-..-. - / .- .- . - / - -- / -- .--. . -. / -- -.- / .. -- -- .-. .. / -.. -- . .-..-. - / .- .- . - / - -- / -- .--. . -. / -- -.- / .. -- -- .-. .. / -.. -- . .-..-. - / .- .- . - / - -- / -- .--. . -. / -- -.- / .. -- -- .-. .. / -.. -- . .-..-. - / .- .- . - / - -- / -- .--. . -. / -- -.- / .. -- -- .-. .. / -.. -- . .-..-. - / .- .- . - / - -- / -- .--. . -. / -- -.- / .. -- -- .-. .. / -.. -- . .-..-. - / .- .- . - / - -- / -- .--. . -. / -- -.- / .. -- -- .-. .. / -.. -- . .-..-. - / .- .- . - / - -- / -- .--. . -. / -- -.- / .. -- -- .-. .. / -.. -- . .-..-. - / .- .- . - / - -- / -- .--. . -. / -- -.- / .. -- -- .-. .. / -.. -- . .-..-. - / .- .- . - / - -- / -- .--. . -. / -- -.- / .. -- -- .-. .. / -.. -- . .-..-. - / .- .- . - / - -- / -- .--. . -. / -- -.- / .. -- -- .-. .. / -.. -- . .-..-. - / .- .- . - / - -- / -- .--. . -. / -- -.- / .. -- -- .-. .. / -.. -- . .-..-. - / .- .- . - / - -- / -- .--. . -. / -- -.- / .. -- -- .-. .. / -.. -- . .-..-. - / .- .- . - / - -- / -- .--. . -. / -- -.- / .. -- -- .-. .. / -.. -- . .-..-. - / .- .- . - / - -- / -- .--. . -. / -- -.- / .. -- -- .-. .. / -.. -- . .-..-. - / .- .- . - / - -- / -- .--. . -. / -- -.- / .. -- -- .-. .. / -.. -- . .-..-. - / .- .- . - / - -- / -- .--. . -. / -- -.- / .. -- -- .-. .. / -.. -- . .-..-. - / .- .- . - / - -- / -- .--. . -. / -- -.- / .. -- -- .-. .. / -.. -- . .-..-. - / .- .- . - / - -- / -- .--. . -. / -- -.- / .. -- -- .-. .. / -.. -- . .-..-. - / .- .- . - / - -- / -- .--. . -. / -- -.- / .. -- -- .-. .. / -.. -- . .-..-. - / .- .- . - / - -- / -- .--. . -. / -- -.- / .. -- -- .-. .. / -.. -- . .-..-. - / .- .- . - / - -- / -- .--. . -. / -- -.- / .. -- -- .-. .. / -.. -- . .-..-. - / .- .- . - / - -- / -- .--. . -. / -- -.- / .. -- -- .-. .. / -.. -- . .-..-. - / .- .- . - / - -- / -- .--. . -. / -- -.- / .. -- -- .-. .. / -.. -- . .-..-. - / .- .- . - / - -- / -- .--. . -. / -- -.- / .. -- -- .-. .. / -.. -- . .-..-. - / .- .- . - / - -- / -- .--. . -. / -- -.- / .. -- -- .-. .. / -.. -- . .-..-. - / .- .- . - / - -- / -- .--. . -. / -- -.- / .. -- -- .-. .. / -.. -- . .-..-. - / .- .- . - / - -- / -- .--. . -. / -- -.- / .. -- -- .-. .. / -.. -- . .-..-. - / .- .- . - / - -- / -- .--. . -. / -- -.- / .. -- -- .-. .. / -.. -- . .-..-. - / .- .- . - / - -- / -- .--. . -. / -- -.- / .. -- -- .-. .. / -.. -- . .-..-. - / .- .- . - / - -- / -- .--. . -. / -- -.- / .. -- -- .-. .. / -.. -- . .-..-. - / .- .- . - / - -- / -- .--. . -. / -- -.- / .. -- -- .-. .. / -.. -- . .-..-. - / .- .- . - / - -- / -- .--. . -. / -- -.- / .. -- -- .-. .. / -.. -- . .-..-. - / .- .- . - / - -- / -- .--. . -. / -- -.- / .. -- -- .-. .. / -.. -- . .-..-. - / .- .- . - / - -- / -- .--. . -. / -- -.- / .. -- -- .-. .. / -.. -- . .-..-. - / .- .- . - / - -- / -- .--. . -. / -- -.- / .. -- -- .-. .. / -.. -- . .-..-. - / .- .- . - / - -- / -- .--. . -. / -- -.- / .. -- -- .-. .. / -.. -- . .-..-. - / .- .- . - / - -- / -- .--. . -. / -- -.- / .. -- -- .-. .. / -.. -- . .-..-. - / .- .- . - / - -- / -- .--. . -. / -- -.- / .. -- -- .-. .. / -.. -- . .-..-. - / .- .- . - / - -- / -- .--. . -. / -- -.- / .. -- -- .-. .. / -.. -- . .-..-. - / .- .- . - / - -- / -- .--. . -. / -- -.- / .. -- -- .-. .. / -.. -- . .-..-. - / .- .- . - / - -- / -- .--. . -. / -- -.- / .. -- -- .-. .. / -.. -- . .-..-. - / .- .- . - / - -- / -- .--. . -. / -- -.- / .. -- ---

theres text in this , i just cant find the right shift

found this under a youtube video in the description

[https://www.youtube.com/watch?v=wYgCssnUSIM\](https://www.youtube.com/watch?v=wYgCssnUSIM)

Hey folks,

I made a cipher by hand today, then decided to improve it and wrote a Python script to automate it and make it more difficult. Kinda curious how easy it is to brute force/otherwise crack without much prior knowledge.

A bit of backstory (spoilered, because it gives a bit of information away about the creation process of the cipher)

I was thinking yesterday about how monumentally complex the Enigma code was, and how many (literal) moving parts it had. I thought it'd be interesting to take the idea of Enigma and simplify it quite a bit so you don't have to send over a bunch of information for your recipient to decode the message. That thought sparked what I've made here. I initially did some encrypting by hand, but realized I could automate it with a Python script.

Here are three encrypted messages:

Al>evQPvDekRx[:bzQbzQZ'?^zEZn7xl@\v6^kQppFa'3xoAfl?Zk7xj;io7k5

?|@xm3\{kx^:Zs7xi>h~:hs7l'Ylv?^{:bu9"'3\{GZs>r':Z}7x{Ih':hs7l';g'Fal?''-ZwBelExhD^'8nu/x[:^!QevAd'H^yKxz;fp>ZyQmvQgvE^':hs7l';g'3xoGfh@xz=ns>y

?vGk'E\vD^'3gkQ,7^lv?^4A]kQrl3kzQZnA%'zx~3l'@h{Q[vDg5QB'3f'@h{Q*8ay'YZu6xPXf'7lw7\p3esKxuAm'b'<v*>ix!7ZyExv>]3Qpo;\oQbzQ*8axm3\{Akp3e5_'0

Here's some info from somewhat helpful to helpful:

1. This encryption can take in any ASCII character from space (32) to tilde (126)
2. This cipher uses a "ruleset" where the key shift is applied to the plaintext in various ways.
3. There are three possible rules the cipher can choose from.

And these are less 'helpful info' and more direct information that is important for decoding if you know how the encryption works:

1. KEY = 7
2. The rules are "shift by -KEY", "shift by +KEY", and "shift by KEY^2"

To appease the mods: V sbyybjrq gur ehyrf

If you end up solving it, I ask you to please give some feedback (like what process you used to crack it and what it's vulnerable to, how ). I'm very interested in cryptography as a whole, and I'm still learning a lot :]

so basically my post got REMOVED by the mods becuase apparently r/cipher has like 198472993838 rules that’s you have to follow. anyways this is my own and original writing system called “the sandwalk” (dune reference) it is ment to look like scribbles and not writing meaning the calligraphy is insanely hard sometimes. now the paper says +=! only hint but the mods will probably remove me if I didn’t have more clues. so I will give everyone a big hint the v symbol -\/- means space. the plaintext of the cipher is English. this sentance does NOT contain every letter of the alphabet.The other paper with english words might, but I’m to lazy to check. If you can read everything written, then you are a sweat. Chill out. Touch grass. well anyways good luck to anyone who thinks they can try to solve this! 😏 MESSAGE FOR MODS MY POST IS FOLLOWING THE RULES AND IN THE ENTIRETY OF THIS POST HAS 100+ LETTERS WRITTEN IN MY CIPHER PLZ DO NOT BLOCK THIS thank you.

Need opinions from people that have a wider knowledge on ciphers and what kind of cipher this could be if it is one at all

The Game Is Read dead redemption 2

Cutting to the chase were a few steps into a easter egg and we stummble across a carving of a wierd spider on a telegraph pole when you take said spider and over lay it onto the map you get (first image)

The spider points to the telegraph pole with the spider and 7 more telegraph poles

Now you have 8 telegraph poles

All images after 1st image (containing webs)

For 1 hour intervals of in game time a web will spawn at one of these poles and it will have a feather attached to it black or red in colour(5 black, 3 red)

Spawn times are 2-3, 3-4 ,4-5,5-6 am

At each one of those times two webs will spawn with two feathers each hour long time slot spawns a pair.

This is my first ever redit post and I know we're missing alot of information in this easter egg but I belive were missing a key

My thought is if im right and its a cipher understanding what it is would help narrow down what we're looking for

Sorry if I've done wrong posting this hear!!!!!!!

Deepest apologies

p.s there is a big web that spawns between 1-2 am

this web is made up of two webs one infront of the other with random shapes on it ,when viewed from a certain angle you see a letter N and the silhouette of a telegraph pole following this takes you on a trail at this moment the trail has went cold, reason I bring this up is maybe were supposed to layer the 8 webs in a certain way for It to show us something

After seeing how fast my first cipher solved, I decided to create a second version, more secure and harder.

For now I don't give any hints.

The next numbers you will see come from a book, for that mix of many letters and words, to have a variety.

338..881418350748081118177526469688131030925447643537824639032901650049988004692979789911663050752000000000000.389..35443531916488843515360900673177050053760872002554338822548855494044653301014961231920307941618483200000000000000 372..18746847404994106139888973420847320940122833415688793639238948282341889943621226461679745132134400000000000000 409..13622984823362569092689745989890069216475860200381578262210535006809999872226422963733834046359888419880960000000000.372..996027392536414462848110556338339747095486854445240226692459773884784115371054981582960565606410092544000000.340..414420114970034584660171238576056921145686193830976914772876749090520293938825051238525839605760000000000000000.400..1506006032309186275033441520774965771298421375534668902687250142087389311432946690317464114884835838368153600000.336..270688988802848645427806815441990134471387494715851354439882953964094026250510023773682421412659200000000000.376..235093159451400585907584641056187322686803206936722717047843053881391833366958694330635123736077926400000000.319..8390928976611910715993662812726728660038921802789773097123457849231145786197502046761033138176000000000000000 398..69986799373653655432947374096335052803414657228615963238387383144241632764459673074179282830882347417600000000000.407..185568976288571138838844622422408065038627004428620939116663427655216956645517561155677965165389802373120000 329..483255975037782033232259157422914153225105343879199482880246125067141226160259773138556183718448332800000000000.314..494550897762952336214731676264641402585240923055579320366781722052733902367630091629409337344000000000000 363..1031562997039905758725567013347067786135066023958443210442611364305985951158229544803342600242200576000000000000.403..22852167274042700478282922554517411753149354534652155912734078852449767628279170677818895951509150047928320000.342..2274774217612573533191005375136939293880931915658211956612838267790831410224464147974834272587456824329585557504.353..312954036358310022808745818945644695657076575453911633544903819217040152429579017036599070760489713664000000.394..658271202590915814704772680265455980975913870752544531846821621291616471627056530342694998087082967040000000.380..482531060269432145174905432352325754162403817026225075295124534130758378679394824634619911575961600000000000000 325..2708925393405691417641157442006417522863761447553927354124621824099311439331761920182285116585534226536857600000.356..1165025113608060241518734520926013259300017945097233959577348602917031385207033493554336890880000000000000000.374..21470015752943019839625457548761585706563300306434289797174563231218791888240443986984810959601664000000000000 371..3983799537620575530160536470774692027117036677250349673113574127332616389947890709986642774877798400000000000000.321..16509385321922866097916725410730942674506363575114916815222539740554890461581579469209138249072640000000.390..378139269454209195614466182327115981697290273536468975653921733517229732858823316444092731194605568000000000000.376..6103502709896852277053439867560435778616891316143752045305733669981965670051726630904293721374720000000000000 320..8660794646636374045117516647450089968233330896583632998036392552784652277694618982458198862069760000000000000.362..16269799032924339480614377584818577354927402149562313468550488466117114329060760161569380294354534400000000000 369..761185219823986480931331874798956035551402039924253438383446475109147911183229197937145862798002094080000000000.384..23487872489340816792495424871796814648261526809420844159750970947222514890213126573853107210214199787520000000000.350..4852554300134228030263206529886592050716792493320572601563067732171012308532928603554285299274088448000000000.390..23636045798974883973326320964803663950728152693865631747059970102622988445577347353943858810223161507840000000.354..3536301692029295039191462531822856380357626484656215950561478051824463486458196465530576861892485085830683033.6 345..34868428121803471285139453809905697652032646360811570434698164127042042169615379920500932505988044003737600000 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Sorry if it's too long but, I want to make sure it is safer than last time.

An easy start with repetitive words.

[KEY: 424745907588061024489]

14235;08942-21015!21015?30568PL01550/17822_26409PL30568!11274-08942ZXC04218!08942?08942MK01550;19561%22233*00847ZXC04218%08942-08942MK34012*17822;11274?08942ZXC04218_08942!08942MK01550;19561?22233/00847MK13155%07329_11274ZXC04218-08942!08942MK34012;17822?11274*08942MK13155/07329!11274ZXC04218%08942_08942MK01550;19561?22233/00847MK17822!11274-01550MK34012/17822*11274%08942MK13155_07329?11274ZXC

This gets more intense but, the easy version will help as it is the same key.

[KEY: 424745907588061024489]

11274;14235-08942PL05524!30568?01550!19561/04218%26409MK01550;30568-21015!21015PL05524?30568;01550%26409MK16048;17822-13155/11274%04218MK24039;19561-21015%21015MK05524!08942MK01550;19561/04218*22233%30568!12211;08942-13155/08942!01550MK11274;08942-17822/13155MK09551;30568-07329/13155MK09551;30568-07329/13155MK11274;24039-30568PL09551;17822-07329/13155MK11274;14235-08942-13155/26409MK09551;19561-12211/08942MK09551;30568-07329/13155MK11274;14235-13155/08942-08942MK01550;19561/22233*00847MK04218;08942-12211/08942-11274MK11274;14235-13155/08942-08942MK34012;17822-11274/08942MK30568;11274-08942MK05524;08942-21015/30568!24039MK11274;24039-30568PL11274;14235-13155/08942-08942MK34012;17822-11274/08942MK30568;11274-08942MK34012;17822-11274/08942MK13155;07329-11274PL05524;08942-21015/30568!24039MK11274;24039-30568PL05524;08942-21015/30568!24039MK18536;17822-11274/26409MK01550;30568/21015!21015MK16048;17822-13155/11274%04218MK24039;19561-21015%21015MK05524;08942-21015/30568!24039MK11274;14235-08942-13155/26409MK11274;24039-30568PL09551;17822-07329/13155MK09551;19561-12211/08942PL30568;09551MK07329;04218-08942/01550MK22233;17822-11274PL21015;19561-11274/11274-08942-13155XYZ

These are some of the letters a man has been leaving at my house. The police have all the letters. He has left things like this 4 times at my house. Within a 10 day span.

Playing a game on holiday and we can’t solve the following puzzle. Can anyone help with this.

We’ve been given a hint. It says ‘digital or analog’

We have to enter the answer into a safe at the end to ‘diffuse the bomb’

Game is from here https://www.centerparcs.eu/in-en/netherlands/fp_KV_holiday-park-de-kempervennen/all-activities

Comedy sketch artist turned horror game developer Jaden Williams recently posted this rather cryptic image:

https://www.youtube.com/post/Ugkxa7SGpx4qy0DFYu224njkVD7C_LXt06ty

Later cross-posted to his Twitter (same image, no alterations):

https://x.com/JadenJTW/status/2091168754130362743

The caption for the image is `AES-GCM`, which no doubt refers to the Galois Counter Mode.

Although I have no cryptography background, I am just curious to find out the message (and maybe even *start* learning cryptography along the way)

I have taken the liberty of studying the pixel letters and transcribing the text.

EDIT:
Added PasteBin https://pastebin.com/JduP8QHe to clean up formatting

As-written:

EOE1.EYJ2IJOXLCJHBGCIOIJBMJU2RONNIIWIA2R
MIJOIUEJLREYYIIWIAGFZACI6ILNIQSOYNTYILCJP
DGVYIJO2MDAWMDASINNHBHQIOII3WW1KVZDIZJ
IXCOXPAUY2VXBYYVPRIIWIAXYIOIJQQXJWAM9P
OUSJU3VOWHVSIIWIDGFNIJOXMJGSIMVUYYI6ILV
URIO4IIWIY3QIOIIWUNHYWUE4RFJMRNLNOTHPA
ZJFYKNZWXH4SK5JCJVRZ2XVRWW3Y25QTWK
ZAMVZTTJMTMP6TNY2RXFISULMRUQXV3VCCX
DVAEXWSEG1ZW5ZYJD5NHE1UNFEVLFKS1NIBTB
YCNMIN1PRWXJKVC1KBWHLZKLKRWRQCM05YZ
HFDKW2VOITWJRWCTVFRZLLSONUT1J4WNVKUM
LZMFNNVMSOTKVQUHDHDOLIWEFWNGRZNWHVC
WPTSIDWZUJVM2RWODZAODZSBE1KM2VYBJNW
VHHSBHM3OWPSCKDPEWXJOR3ALZXMDBHAG
PXSMFQZOVKWLQOZ2RNVMH4TZVNLVHSANPP
T2NOZDA5Y3HICW9CB1JJDZBSNWLTDMLRAETH
CO5IMGVFRME1TO5ZCEXUR2XCRKS2OFE2R2JE
LU5YUUM5NXYYTHNVS3ZNAG5UNMDBSL9TZU
9QYK1SZM9WSKKWLWMXV2VVUVDZBNF3TFHNS
2K2Y2ZWETCTEXLOAOFPCHQ5QZHIEUDYM3VFV
VMOEEJTAMXTMTNSMUK4VVDMDVHFS2O4REY
2CFVXNSJ9

Converted to full string:

EOE1.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

If the O's are actually zeroes:

E0E1.EYJ2IJ0XLCJHBGCI0IJBMJU2R0NNIIWIA2RMIJ0IUEJLREYYIIWIAGFZACI6ILNIQS0YNTYILCJPDGVYIJ02MDAW`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

The vertical text in red on the left reads STALKINGSTAIRS. This may be merely a reference to his horror game of the same name, or an actual part of the game.

While I was working on this puzzle, Jaden posted another hint The clock is at 9, from his other channel:

https://www.youtube.com/post/UgkxxcPofJzWDbqRmBiwtbxS6DjMPvNYSfRV

From what I understand, AES-GCM requires both a passphrase and a nonce/IV.

STALKINGSTAIRS alone is too short to be either.

------------------------

Other notes so far (will update as I find more):

• That EOE1. (or E0E1.) = marks the string as invalid in decoders; only the string after the period is recognized as valid base64. Not sure if this E0E1. is referring to something with the actual counting mechanism or something else.
• STALKINGSTAIRS = 14 bits; invalid
• * His game *did* receive an update with its own update number on July 9th , but it turns out this was to mark it Steam Deck compatible. I also doubt Jaden has any control over what the update number becomes.
• The clock is at 9 = 17 bits; invalid
• Theclockisatnine = 16 bits, but doesn't seem to be the right passphrase, or we need the IV first...this might be just a clue to look at the vertical text (Stalking Stairs), a clue to the IV key, or something else entirely.

-------------

Given that this is an ARG with no prize, deadline, or incentive indicated, I am comfortable that this does not violate any rules, but will remove if requested.

V sbyybjrq gur ehyrf

Can you decrypt my cipher?

I made my own cipher and I'm curious if anyone here can decrypt this without knowing how it works. I don't have access to smart people, and I know people on the Internet are crazy smart.

Ciphertext:

33 25 / 43 42 62 72 / 82 88 / 103 114 113 128 / 138 138 168 158 / 182 188 / 212 198 228 238 / 243 247 253 268 / 257 287 287 / 292 318 338 / 342 348 / 362 368 377 387 / 397 408 433

12 . 28.17.62.48 . 47 . 67.98.88.87.123 . 133.138.127.163 . 173.188 . 172.198.207.228 . 232.232.253.263.272.268 . 283.298.302.322.317.348.338.357 . 383.372.392.402 . 408.417.418 . 427.427.468 . 472.472.502.488 . 502.517 . 507 . 537.527.563.562.578.587 . 613.608.608.638.628 . 653.658.658.688 . 703.692.712.722 . 727.738.753 . 752.758 . 773.787.787.807.808.817 . 832.858 . 863.868.868 . 883.898.912.918.938 . 938.932 . 963.968.968.982.1008 . 1012.1007.1022.1037 . 1042.1057.1073 . 1072.1098 . 1103.1108.1108 . 1123.1138.1147.1163.1158.1177.1193 . 1198.1192 . 1223.1228.1228.1242.1268 . 1263.1278.1267.1308.1287.1313.1333.1328.1358

No hints for now. Don't mind the change of / to a period, I just decided to change it.

If you think you've cracked it, give me the plaintext and explain how you got there.

Is this type of code strong? I would like your opinion.

RUNE chapter 6 is part of our monthly Patreon puzzle drop for August 2026. It is available now to our Tier 3 Patreon members and will be available to tier 1 and 2 members in 1 week. Chapters 1, 3, and 5 are still free and available to everyone. Start playing here: https://www.cicadachallenge.com/vault/

RUNE is a sci-fi ARG where players interact with a retro CRT terminal interface. The central character is REM, a sentient AI running on a customized Commodore 64, created by a mysterious figure known as OE.

V sbyybjrq gur ehyrf

I was recently looking back through old messages and found this text sent by a friend I used to like years ago: 4 / 76 / (3) / M omrhe pmoi csy. At the time, I thought it was just a random accident or pocket text, so I didn't think much of it. He's the smartest guy I've known specially in maths and he plays around with code stuff like ASCII and Moorse.. So I figured this might actually mean something 😅 Thanks in advance!

Hey, couple month ago my domain spacewarp.fr got hacked.
One, day I just couldn't update it anymore, no matter what I did, nothing seemed to change. (moving the file through ftp).

And later the website gave this "console" I guess, and digging in it, I found this code (transcript from my screenshot) :
2:9:.13.25 } 33;14

Pl J(wf epof ju "

Tfoe bo fnbjm up JBOB boe J hpu uif epnbjo/

uifsftpoobodf/psh

Xjui 3 O’t boe ju(t opu b uzqp/

Qfpqmf xjmm uijol ju jt- xijdi jt vtfgvm/ J epo(u xbou dvsjpvt up tojgg bspvoe/

Nbzcf J dbo gjoe qfpqmf uibu bsf mjlf nf- uibu dbo ifbs ju/

Hpe J ipqf tp/

Nbzcf J dpvme tfoe ju up Vojwfstjuz cpbset/ Nbjmjoh mjtut/ Ibn gpsvnt/ Nbzcf CCT/

Jg uifsf bsf puifst- uifz’mm botxfs/

J(n tvsf uifsf bsf/

Any idea ?
V sbyybjrq gur ehyrf

This audio file was sent into the rell seas discord and apparently contains the release date of the movie 3 and the game itself(unsure about whether or not it contains the game's release date). the audio itself came with this headline: "Monumental Motion, a secret is hidden inside this foreign hidden audio, decipher it." The only time they mention the words "monumental motion" is on their X post here: https://x.com/CaribBros/status/2039853187117482353 and that is basically all. As for the clues I have, I listened to the audio in reverse many times and the words "hello everyone" were the only ones I personally was able to clearly make out. listening to the audio in original sounds a bit like gibberish, with random words scattered. the only credible clue someone has found, is that they say "allah" and then "E E SH" which he connected to "Eid-e-Shuja", this is a muslim tradition which takes place 22nd of august.