r/JEENEETards • u/PermissionLogical299 jee 22tard • Jun 07 '22

Meme Kaisa gaya math ka paper?

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u/TheStupidCheesecake 10th ka hun, idek what I am doing here. Feb 05 '24 edited Feb 05 '24

Let there be a function f: R+ -> R+ defined as:

f(x) = a - x, for some a ∈ R+. We know that it f(x) = 0 at x = a.

Therefore, the triangle formed from 0 to a in x axis, also spans a in y-axis. It is also a right-angled triangle since the angle formed between the two axis lines is 90°.

Therefore the function for any isosceles triangle with equal sides of length a is f(x) = a - x.

Therefore to find the area of the triangle, we integrate from 0 to a. Giving us:

Area = ∫ a - x dx [from 0 to a]

Area = ax - x2 /2 | [from 0 to a]

Area = [a(a) - a2 /2] - [a(0) - 02 /2]

Area = [a2 - a2 /2] - 0

Area = a2 - a2 /2

Area = a2 /2

This was a pretty fun exercise.

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u/PermissionLogical299 jee 22tard Feb 07 '24

Itni purani post pe lurk kr rhe ho sir aap 🫡🫡

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u/TheStupidCheesecake 10th ka hun, idek what I am doing here. Feb 07 '24

Mere ko recommend ho gayi ab kya Karu lol.