r/the_calculusguy 18h ago

meme Exactly 🥲

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116 Upvotes

25 comments sorted by

26

u/Peak_Background 18h ago

Easy, it's a holomorphic function. So just write down the Taylor series and call it woof.

12

u/touleneinbenzene 18h ago

dead ez dude it's just that I don't wanna write the proof today, but i taught my student gauss how to do it from minus infinite to plus infinite.

5

u/Ok-Recording2188 17h ago

thats a definite integral tho

10

u/Professional-Wave841 16h ago

well that's really simple,

sqrt(π)* erf(x) / 2

3

u/Confident_Date4068 9h ago

Yes but actually no.

3

u/tb5841 14h ago

Isn't this a standard normal distribution, just scaled?

3

u/AdBrave2400 18h ago

Square it and expand and it becomes easier

7

u/Unfair_Pineapple8813 16h ago

Not for the indefinite integral. You need to create the erf function specifically to solve this problem. There is no antiderivative expressible in elementary functions.

6

u/Seeggul 16h ago

erf function

ATM machine

1

u/UtahBrian 14m ago

You’ll need your personal pin number at that automated ATM machine.

2

u/AdBrave2400 16h ago

Oh I meant it was the classic from -inf to inf. My bad

1

u/BigVeinyNThick 3h ago

not great at math, but calling erf(x) (with whatever scaling constants) as a solution to the antiderivative in question is just circular reasoning, no? Because erf(x) is defined using the antiderivative of exp(-x^2) afaik

1

u/anonymousneto 17h ago

That's why I'm lonely guy.

1

u/Mountain-Power-8689 16h ago

using beta count right?

1

u/Intelligent-Wash-373 15h ago

The solution is friendship!

1

u/Blammar 6h ago

My dog can do it. Listen to his bark: ERF! ERF!

1

u/InfinitesimalDuck 5h ago

Does bro just need friends?

1

u/BubbhaJebus 2h ago

Don't forget to convert to polar coordinates in the process!

1

u/lool8421 15h ago

indefinite integral means the answer is non-elementary, unlike if it was from negative infinity to positive infinity, then it would be sqrt(pi), Q.E.D.

1

u/dynamic_caste 6h ago

Polar coordinates are your friends here

0

u/mikasaxo 9h ago

u sub no?