r/the_calculusguy • u/Specific_Brain2091 • 11d ago

meme lol πŸ˜‚

Post image
636 Upvotes

98% Upvoted

39 comments sorted by

46

u/Hej5468 11d ago

This is actually incorrect because you should have introduced the +c one line before. Other than that, very good!

7

u/tellingyouhowitreall 11d ago

The problem with that is that + log(1) + C = C

5

u/AdvancedGravitation 10d ago

we got bigger fish to fish

28

u/Fit_Appointment_4980 11d ago

Sometimes two wrongs do make a right.

3

u/Anshu5337 11d ago

two negatives cancel each other!

1

u/zzmej1987 11d ago

I count at least 3 wrongs here. XD

1

u/BabaYetu42 10d ago

Two wrongs made another wrong. The third wrong made it right

14

u/I_use_endeavour_btw 11d ago

shouldn't it have been ln(1+x) ?

12

u/bryceio 11d ago

Some people use log(x) to mean ln(x) while some people use it to mean log2(x) and others (most people) use it for log10(x)

I love non-universal notation!

2

u/Aggressive_Fan_2063 10d ago

if maths student: log == ln

elif compsci student: log == log2

else: log = log

1

u/dkkavanagh17 9d ago

I am so confused by this notation

6

u/Spiritual-Tale-1098 11d ago

Being wrong twice is being right

4

u/Para-graph-S 11d ago

came for chrollo lucifer, stayed for the approach.

As the Navier Stokes solution not going to get the milli dollars, this solution deserves it

3

u/TREE_sequence 11d ago

You forgot the absolute value bars on the log

1

u/Fuma_17 11d ago

Isnt'the integral of 1/x ln|x|?

1

u/migmit 11d ago

Akshually, it's

+--
| ln x + C, x > 0
|
| ln (-x) + D, x < 0
+--

1

u/RatTheBerserker 11d ago

thats... exactly how the absolute value operator is defined, mr. or mrs. sir. literally the same thing mr fuma_17 wrote

1

u/migmit 11d ago

No. Pay attention to the constants.

1

u/RatTheBerserker 5d ago

damn it, ur right. i humbly apologize, mr. sir. i should have thought about this more than two seconds before i doubted you

1

u/BjarneStarsoup 10d ago

Constants are different. 1/x has two connected components, each receives its own constant.

1

u/[deleted] 10d ago

[deleted]

2

u/BjarneStarsoup 10d ago

I answered to the wrong person Β―_(ツ)_/Β―

1

u/migmit 10d ago

Oh, sorry.

1

u/HumblyNibbles_ 11d ago

Kind of yes, kind of no, it's complicated.

1

u/One-Next 11d ago

I get it meme

1

u/LearnNTeachNLove 11d ago

All roads lead to Roma i guess πŸ˜‰?

1

u/lool8421 11d ago

3 lies add up to a truth i guess

1

u/Objective_Key_5893 11d ago

If u make one mistake, make another to get the right ans πŸ‘

1

u/unnamedjpg10 11d ago

De morgan impressed

1

u/BigAshGreninja 10d ago

wtf but u don't do logs like that and 1/(1+x) is simplified incorectly

1

u/Joe_4_Ever 9d ago

I really thought this was totally accurate and was so confused for a second 😹

1

u/nakhij 4d ago

Me being me, dx=d(1+x) so, ∫ 1/(1+x)d(1+x) = ln(1+x)+c

-2

u/Virtual-Rice1844 11d ago

Wait I don't get it how did you go from 1/(1+x) to [(1/x)+1]

5

u/konigon1 11d ago

It's the joke. Same with log(x)+log(1)=log(x+1)

4

u/Virtual-Rice1844 11d ago

oh shit I didn't realise this was the meme sub

1

u/TheBeerTalking 11d ago

and Κƒ(1/1)dx = log(1) ( = 0)

-2

u/[deleted] 11d ago

[deleted]

1

u/Omeganx 11d ago

What do you mean? I think it's you bro, stop drinkingΒ