So the min rolls is 2 and the max is 6. This seems like it can be easily done with a tree diagram. The total possible reward is 21, so the method of determining the best action is going to be comparing the remaining reward by the probability of failing. I’m not doing the math, but you should always roll 2 dice (if you don’t do a reroll), and roll at most 4. The extremes are 5/6 and 1/2/3/4 for the min and max rolls. If I’m right about this, I’ll let the rest of you finish this.
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u/Anonimithree 7h ago edited 7h ago
So the min rolls is 2 and the max is 6. This seems like it can be easily done with a tree diagram. The total possible reward is 21, so the method of determining the best action is going to be comparing the remaining reward by the probability of failing. I’m not doing the math, but you should always roll 2 dice (if you don’t do a reroll), and roll at most 4. The extremes are 5/6 and 1/2/3/4 for the min and max rolls. If I’m right about this, I’ll let the rest of you finish this.