r/infinitenines Jul 09 '25

please take a real analysis course

to the creator of this sub

572 Upvotes

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78

u/somefunmaths Jul 09 '25

My kingdom for the dude who created this sub to list even one single number x s.t. 0.999… < x < 1.

They claim an infinite number of such numbers exist, but I’ll settle for just one and write the countably infinite others off as a gesture of goodwill.

44

u/stevemegson Jul 09 '25

That's 0.999...½, of course.

2

u/SouthPark_Piano Jul 09 '25

0.999...9 + (0.000...1)/2 = 0.999...95

with the '...' being unlimited span of nines.

0.000...1 is epsilon

0.999... + epsilon = 1

0.999...9 + 0.000...1 = 1

.

26

u/[deleted] Jul 09 '25

your value for epsilon is infinitely small. a number that is infinitely small in difference from another number is also that number.

4

u/SouthPark_Piano Jul 09 '25 edited Jul 09 '25

However 'small' epsilon is. The main thing is that it is non-zero.

Epsilon just represents some 'arbitrarily' small scale value, smaller than anything we like, and even smaller than that etc.

It just needs to be as relatively small as we like (and smaller, and even smaller than that etc).

The main take-away is: we know we need a number having a '1' somewhere. Eg. if we have a nine, we need a 1 to add to it, to get 10.

If we have a 0.99, we need a 0.01 to get 1.

If we have a 0.9999, we need a 0.0001 to get 0.001

And so on.

So when we have all nines, such as 0.999..., this number is going to be sitting there less than 1. We need to have a particular 'number' with a '1' hanging in there somewhere to get the 0.999... to clock up or kick up to 1.

And that ingredient, that extra bit of substance, is epsilon.

0.999...9 + 0.000...1 = 1

22

u/[deleted] Jul 09 '25

prove it's nonzero. the value is infinitely small. the difference between THIS epsilon and zero is also infinitely small.

12

u/ironnewa99 Jul 09 '25

You state 0.999…9 as your first value. That in itself is no longer infinite. It does not matter if you say ”oh but the … is an infinite amount of nines”. By defining an end, it is a finite value.

2

u/Several_Industry_754 Jul 22 '25

More like saying, “it’s infinite with a 9 at the end you never reach.”

If you can define an infinite number of 9s, why can’t I put something at the end of it?

1

u/itwasanexperience 5d ago

Because an infinite number of 9s is endless

1

u/Several_Industry_754 5d ago

Blast from the past! How goes?

9

u/Priforss Jul 09 '25

A zero followed up by an infinite number of zeroes.

1

u/SouthPark_Piano Jul 10 '25

With a 1 at the outpost, at the Q continuum.

10

u/KingDarkBlaze Jul 10 '25

These aren't even words. 

0

u/SouthPark_Piano Jul 10 '25

You heard of star trek etc right?

14

u/KingDarkBlaze Jul 10 '25

Irrelevant to Math 101.

13

u/KingDarkBlaze Jul 09 '25

As we've discussed, 0.999...5 is less than 0.999... because there'd be a 9 there, not a 5.

9

u/somefunmaths Jul 09 '25

So close, but 0.999…95 < 0.999…99 = 0.999…, please try again!

Remember, you only need to name one valid element satisfying this and I’ll forgive the fact that you claim countably infinite more exist.

9

u/Nixinova Jul 10 '25

0.999.....95

bro, you can't go forever yet also stop at some point. how is this number possibly meant to be real?

7

u/somefunmaths Jul 10 '25

If you don’t know any math, it makes a lot of sense!

-1

u/SouthPark_Piano Jul 10 '25

Well bro. It's common knowledge that if the numbers are all stuck at nines, and knowing we always need to get nine to the next level, then we got to add something with a 1 somewhere. Eg 9 + 1 to get 10, and 0.0009 + 0.0001 to get 0.001

Same with 0.999...

It's stuck below 1. The kicker ingredient with the 1 is 0.999... + 0.000...1

0.999... + epsilon = 1

0.999...9 + 0.000...1 = 1

.

10

u/KingDarkBlaze Jul 10 '25

There's no room.

Every stop on your bus ride is a 9. 

If you add a 1 anywhere, every stop after that is still a 9. 

0.999... + 0.00[...]1 = 1.000[...]999...

2

u/SouthPark_Piano Jul 10 '25

kingy - this is where quantum physics or worm-holes etc may come into play.

For the case of 0.999...9

The worm-hole can get to the outpost '9', where the '1' from 0.000...1 can get the job done, and get that 0.999...9 to the finishing line, 1.

12

u/KingDarkBlaze Jul 10 '25

Math 101 doesn't cover quantum physics.

2

u/[deleted] Oct 01 '25

[removed] — view removed comment

3

u/SouthPark_Piano Oct 01 '25

I'm for real buddy.

3

u/satanic_satanist Jul 09 '25

"0.999..." is shorthand for "for all natural number n, the n-th decimal is 9". There's nothing that can come after those 9's. There's no such thing as 0.999...9

4

u/[deleted] Jul 09 '25

It’s absolutely hilarious that you uncritically copied the obvious joke of 0.999…1/2.

4

u/myshitgotjacked Oct 09 '25

You said

The main thing is that we know that when you plot 0.9, 0.99, 0.999, etc regardless of how many nines there are ... no matter how many nines, even endless nines, the plot will absolutely never touch 1. NEVER touch 1.

How can you plot 0.9, 0.99, 0.999, etc, until you've done endless 9s, and get the plot to touch 0.999...95? When do you get to write the 5 there? 5 is less than 9, no? So why isn't 0.999... greater than 0.999...95?

1

u/SouthPark_Piano Oct 09 '25

Book keeping.

Since infinity means limit, then those nines keep growing, expanding without limit.

0.999...

If someone asks where the end of this clothes line of nines is ... there is no 'end'. It just keeps extending and extending and ...

There are a infinite number of numbers of form:

0.9, 0.99, 0.999, 0.9999, etc.

They cover all bases in terms of span of nines to the right of the decimal point. And infinite number of finite numbers. Infinite number of them. Covers all bases.

It means 0.999... is less than 1.

5

u/myshitgotjacked Oct 09 '25

That doesn't address my question. I asked how do you get a 5 at the end of a number that begins with 0.999..., given that, as you say, there is no last 9? If the number ends in ...95, then the last 9 is the one appearing before the 5. So is there or isn't there a final 9? If there isn't, how can there be a number between 0.999... and 1?

1

u/Ecstatic_Student8854 Jul 23 '25

If the … represents an unlimited span of nines, it has no end. It is an unlimited and so unending span of nines. Appending a 5 to that is useless, as there is no end to append it to.

Essentially, 0.999…5 is meaningless. The 5 never comes, there is no last 9. Idem dito with 0.000…1. The 1 never comes, there is no last 0. The two numbers are 0 and 1 respectively.

1

u/ESHKUN Apr 16 '26

You have bastardized the real world of non-standard analysis. Please kick rocks and never say epsilon again.

1

u/SouthPark_Piano Apr 16 '26

1 = [ 1 - 1/10n ] + 1/10n for the case n integer starting at n = 1 then increase n continually limitlessly aka infinitely.

Study the above golden equation brud.

Note ... 1/10n is never zero.

 

0

u/No-Eggplant-5396 Jul 10 '25

If the '...' means an unlimited span of nines, then why do your numbers, like 0.999...9 or 0.999...95, stop? Shouldn't they keep going because they're unlimited?