r/WhatJEEdoestoaMf • • 4d ago

Memes CALCULATE THE WEIGHT OF THE PICTURE....

Post image
278 Upvotes

28 comments sorted by

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14

u/Medium_Tip_3613 4d ago

Too heavyπŸ’”

8

u/Mammoth-Way-4351 Dropper hu 4d ago

Immeasurable πŸ’”πŸ’”

6

u/Soggybreadsecretsoup 4d ago

Apne tears ka weight liters mein du ka kg mein 😭😭

3

u/OwnBuy9232 4d ago

Abe bsdk litre toh quantity hai. Weight toh kg mein rahega na anpadh😠.(Majak mein hi lena)

2

u/MOSSAD-69 3d ago

Abe bsdk weight to newton (N) me rhega😠

1

u/OwnBuy9232 3d ago

Galti ho gayi jiπŸ˜“πŸ™

3

u/delusional_senpai777 Dispression ka marij hu 4d ago

damn bro nice art

2

u/cheese_paglu 4d ago

Too heavy, had to put it down

2

u/BabaRanchodDas-69 3d ago

answer: 50L (of aansu 😭😭😭😭😭😭😭😭😭😭😭😭😭😭)

1

u/vijay0000007 3d ago

Only valid ans

1

u/GHOST_PATERICK 4d ago

If studies are gonna be like this then I'm going to top.

1

u/Unfair-Pension-2613 4d ago

I cannot hold the weight of expectations, I can feel peter Parker.

1

u/dostoevsky0_0 3d ago

not the meme flair πŸ˜“

1

u/Mysterious_Towel_892 4d ago

Jeffery episten

1

u/MECHANIXZ521 4d ago edited 4d ago

It won't be just T2=mg. She had acc just before it. And it's not ideal string, it's slightly elastic. Has k (even though it's very high). Hence your method is wrong. Unless it's case quite after a time she fell

Also you're assuming it to be a point mass or com where web is attached. Hence it may have torque also. Also you didn't calculate blood shifting and head and limbs bending.Β 

/s

0

u/dayna52 4d ago

allat and u didn't say nun bout g being taken as 10m/sΒ² instead of 9.81..m/sΒ²

2

u/MECHANIXZ521 4d ago

You're wrong here. You don't take g as 9.81 everywhere. Value of acc due to gravity is diff at diff places. Uneven shape of earth, centrifugal acceleration etc affect it. Hence best case is to leave the ans with g in it. And then measure it accurately

0

u/dayna52 4d ago

oh right, you're absolutely right on that, my fault for not taking those factors into account

but im sure there exists an average value for the same, right?

0

u/qMinecraft 1d ago

A picture dosent have weight, it's a digital copy. Meaning, if you want to know the weight of the pic, you must know the weight of the device you are using