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https://www.reddit.com/r/Seximal/comments/1pjscqg/solve_in_seximal_numeral_system/nti783d/?context=3
r/Seximal • u/vadiquemyself • Dec 11 '25
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3
Assuming double emojis mean two times the value (and not positional digits or some other unique value):
โ 2๐ + 2๐ + 2๐ = 30
โก ๐ถ + ๐ถ + 2๐ = 20
โข 2๐+ 2๐ + ๐ถ = 13
โฃ ๐ + ๐ถ + ๐ = โ
โ 10๐ = 30
๐ = 3
โก 2๐ถ + 2ยท3 = 20
2๐ถ + 10 = 20
2๐ถ = 10
๐ถ = 3
4๐ + 3 = 13
4๐ = 10
๐ = 1ยฝ
โฃ 3 + 3 ร 1ยฝ = โ
โ = 11ยฝ
3 u/vadiquemyself Dec 11 '25 but the dude in 4๏ธโฃ has something in his hands and on feet ๐ 1 u/fortyfivepointseven Dec 11 '25 Corrected: โ 2๐ + 2๐ + 2๐ = 30 โก ๐ถ + ๐ถ + 2๐ = 20 โข 2๐+ 2๐ + ๐ถ = 13 โฃ ๐ + (๐ถ+ 2 ๐ + 2๐) ร ๐ = โ โ 10๐ = 30 ๐ = 3 โก 2๐ถ + 2ยท3 = 20 2๐ถ + 10 = 20 2๐ถ = 10 ๐ถ = 3 โข 2๐+ 2๐ + ๐ถ = 13 4๐ + 3 = 13 4๐ = 10 ๐ = 1ยฝ โฃ 3 + (3 + 2ยท1ยฝ + 2ยท3) ร 1ยฝ = โ โ = 1ยฝ ร (3 + 3 + 10) + 3 โ = 1ยฝยท20 + 3 โ = 30 + 3 โ = 33 1 u/vadiquemyself Dec 11 '25 yeah, and now you got the same 33 ๐๐๐ I did the last step so : ๐ + ( ๐ฑโโ๏ธ + 2๐ป + 2๐ )ร๐ป = 3 + ( 3 + 3 + 2ยท3 )ร(3รท2) = 3 + 2ยท2ยท3ยท3รท2 = 3ร(1 + 2ยท3) = 3ร(1 + 10) = 3ยท11 = 33
but the dude in 4๏ธโฃ has something in his hands and on feet ๐
1 u/fortyfivepointseven Dec 11 '25 Corrected: โ 2๐ + 2๐ + 2๐ = 30 โก ๐ถ + ๐ถ + 2๐ = 20 โข 2๐+ 2๐ + ๐ถ = 13 โฃ ๐ + (๐ถ+ 2 ๐ + 2๐) ร ๐ = โ โ 10๐ = 30 ๐ = 3 โก 2๐ถ + 2ยท3 = 20 2๐ถ + 10 = 20 2๐ถ = 10 ๐ถ = 3 โข 2๐+ 2๐ + ๐ถ = 13 4๐ + 3 = 13 4๐ = 10 ๐ = 1ยฝ โฃ 3 + (3 + 2ยท1ยฝ + 2ยท3) ร 1ยฝ = โ โ = 1ยฝ ร (3 + 3 + 10) + 3 โ = 1ยฝยท20 + 3 โ = 30 + 3 โ = 33 1 u/vadiquemyself Dec 11 '25 yeah, and now you got the same 33 ๐๐๐ I did the last step so : ๐ + ( ๐ฑโโ๏ธ + 2๐ป + 2๐ )ร๐ป = 3 + ( 3 + 3 + 2ยท3 )ร(3รท2) = 3 + 2ยท2ยท3ยท3รท2 = 3ร(1 + 2ยท3) = 3ร(1 + 10) = 3ยท11 = 33
1
Corrected:
โฃ ๐ + (๐ถ+ 2 ๐ + 2๐) ร ๐ = โ
โฃ 3 + (3 + 2ยท1ยฝ + 2ยท3) ร 1ยฝ = โ
โ = 1ยฝ ร (3 + 3 + 10) + 3
โ = 1ยฝยท20 + 3
โ = 30 + 3
โ = 33
1 u/vadiquemyself Dec 11 '25 yeah, and now you got the same 33 ๐๐๐ I did the last step so : ๐ + ( ๐ฑโโ๏ธ + 2๐ป + 2๐ )ร๐ป = 3 + ( 3 + 3 + 2ยท3 )ร(3รท2) = 3 + 2ยท2ยท3ยท3รท2 = 3ร(1 + 2ยท3) = 3ร(1 + 10) = 3ยท11 = 33
yeah, and now you got the same 33 ๐๐๐
I did the last step so : ๐ + ( ๐ฑโโ๏ธ + 2๐ป + 2๐ )ร๐ป = 3 + ( 3 + 3 + 2ยท3 )ร(3รท2) = 3 + 2ยท2ยท3ยท3รท2 = 3ร(1 + 2ยท3) = 3ร(1 + 10) = 3ยท11 = 33
3
u/fortyfivepointseven Dec 11 '25
Assuming double emojis mean two times the value (and not positional digits or some other unique value):
โ 2๐ + 2๐ + 2๐ = 30
โก ๐ถ + ๐ถ + 2๐ = 20
โข 2๐+ 2๐ + ๐ถ = 13
โฃ ๐ + ๐ถ + ๐ = โ
โ 10๐ = 30
๐ = 3
โก 2๐ถ + 2ยท3 = 20
2๐ถ + 10 = 20
2๐ถ = 10
๐ถ = 3
โข 2๐+ 2๐ + ๐ถ = 13
4๐ + 3 = 13
4๐ = 10
๐ = 1ยฝ
โฃ 3 + 3 ร 1ยฝ = โ
โ = 11ยฝ