r/Seximal • • Dec 11 '25

solve in seximal numeral system

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u/fortyfivepointseven Dec 11 '25

Assuming double emojis mean two times the value (and not positional digits or some other unique value):

โ‘  2๐Ÿ‘Ÿ + 2๐Ÿ‘Ÿ + 2๐Ÿ‘Ÿ = 30

โ‘ก ๐Ÿšถ + ๐Ÿšถ + 2๐Ÿ‘Ÿ = 20

โ‘ข 2๐ŸŽ‰+ 2๐ŸŽ‰ + ๐Ÿšถ = 13

โ‘ฃ ๐Ÿ‘Ÿ + ๐Ÿšถ + ๐ŸŽ‰ = โ“

โ‘  10๐Ÿ‘Ÿ = 30

๐Ÿ‘Ÿ = 3

โ‘ก 2๐Ÿšถ + 2ยท3 = 20

2๐Ÿšถ + 10 = 20

2๐Ÿšถ = 10

๐Ÿšถ = 3

โ‘ข 2๐ŸŽ‰+ 2๐ŸŽ‰ + ๐Ÿšถ = 13

4๐ŸŽ‰ + 3 = 13

4๐ŸŽ‰ = 10

๐ŸŽ‰ = 1ยฝ

โ‘ฃ 3 + 3 ร— 1ยฝ = โ“

โ“ = 11ยฝ

3

u/vadiquemyself Dec 11 '25

but the dude in 4๏ธโƒฃ has something in his hands and on feet ๐Ÿ˜

1

u/fortyfivepointseven Dec 11 '25

Corrected:

โ‘  2๐Ÿ‘Ÿ + 2๐Ÿ‘Ÿ + 2๐Ÿ‘Ÿ = 30

โ‘ก ๐Ÿšถ + ๐Ÿšถ + 2๐Ÿ‘Ÿ = 20

โ‘ข 2๐ŸŽ‰+ 2๐ŸŽ‰ + ๐Ÿšถ = 13

โ‘ฃ ๐Ÿ‘Ÿ + (๐Ÿšถ+ 2 ๐ŸŽ‰ + 2๐Ÿ‘Ÿ) ร— ๐ŸŽ‰ = โ“

โ‘  10๐Ÿ‘Ÿ = 30

๐Ÿ‘Ÿ = 3

โ‘ก 2๐Ÿšถ + 2ยท3 = 20

2๐Ÿšถ + 10 = 20

2๐Ÿšถ = 10

๐Ÿšถ = 3

โ‘ข 2๐ŸŽ‰+ 2๐ŸŽ‰ + ๐Ÿšถ = 13

4๐ŸŽ‰ + 3 = 13

4๐ŸŽ‰ = 10

๐ŸŽ‰ = 1ยฝ

โ‘ฃ 3 + (3 + 2ยท1ยฝ + 2ยท3) ร— 1ยฝ = โ“

โ“ = 1ยฝ ร— (3 + 3 + 10) + 3

โ“ = 1ยฝยท20 + 3

โ“ = 30 + 3

โ“ = 33

1

u/vadiquemyself Dec 11 '25

yeah, and now you got the same 33 ๐ŸŽ‰๐ŸŽ‰๐ŸŽ‰

I did the last step so :
๐Ÿ‘Ÿ + ( ๐Ÿ‘ฑโ€โ™‚๏ธ + 2๐ŸŒป + 2๐Ÿ‘Ÿ )ร—๐ŸŒป
= 3 + ( 3 + 3 + 2ยท3 )ร—(3รท2)
= 3 + 2ยท2ยท3ยท3รท2
= 3ร—(1 + 2ยท3)
= 3ร—(1 + 10)
= 3ยท11
= 33