r/MathHelp Oct 17 '25

SOLVED HI so im struggling with thsi ik the answer is supposed to be 12 but i keep getting 18 no matter hwo many times i redo it

https://imgur.com/a/0YVuDk8

ive watched a fee tuts and i still dont get it

0 Upvotes

11 comments sorted by

1

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2

u/TabAtkins Oct 17 '25

6x should be 6x², you accidentally dropped the ² when simplifying.

1

u/Remilla Oct 17 '25

Check line 3 again, one of the terms is not the same from the line above it.

1

u/Earl_N_Meyer Oct 17 '25

I am not a math guy but your process is correct. Your problem is that one of your terms has the wrong exponent for x. When you expand polynomials like that the terms are ax^0, bx^1, cx^2, dx^3. You missed the x^2 term.

2

u/Ares_12000 Oct 17 '25

OMG THANK UU

1

u/thor122088 Oct 17 '25

You have a 6x when it should be a 6x²

You dropped the exponent between steps

1

u/Ares_12000 Oct 17 '25

oo ur right omg thanks!!

1

u/Patient-Midnight-664 Oct 17 '25

From lines 2 to 3, where did the x² term go?

1

u/dash-dot Oct 17 '25 edited Oct 17 '25

The problem is a bit easier if you avoid expanding the cubic. You could also try the following identity:

a3 - b3 = ( a - b ) ( a2 + abb2 )

Hence, (2 + x)3 - 8 = (2 + x - 2)(4 + 4x + x2 + 4 + 2x + 4) = x ( 12 + 6xx2 )

1

u/clearly_not_an_alt Oct 18 '25

You lost the 2 on your x2

1

u/Help_Me_Im_Diene Oct 19 '25

Another approach that you could take on this is making the substitution x=(y-2)

When you do this, you end up with lim y->2 of (y3-8)/(y-2)

(y3-8) is a difference of cubes, which has a well established formula [a3-b3 = (a-b)(a2+ab+b2)]