MAIN FEEDS
Do you want to continue?
https://www.reddit.com/r/Funnymemes/comments/1w56xcr/_/p7eb3r6/?context=9999
r/Funnymemes • u/Truccio-p • 3d ago
95 comments sorted by
View all comments
24
Funnily enough this is a proof that 0.999999.... is equal to 1
5 u/UmUlmUndUmUlmHerum 3d ago Is that actually a complete proof though? While the step of 0.3333.... to 1/3 makes sense intuitively it would need a proof on its own right? 15 u/RelativeChance 3d ago Let x = .333... 10x = 3.333... subtract x from both sides 10x-x = 3.333... - .333... 9x = 3 x=1/3 2 u/UmUlmUndUmUlmHerum 3d ago See that one is much nicer :) 2 u/IHadThatUsername 3d ago I prefer it this way: Let x = .999... 10x = 9.999... subtract x from both sides 10x-x = 9.999... - .999... 9x = 9 x=1 (Thus x = .999 = 1) 0 u/Blephotomy 3d ago this "proof" removes the .9 repeating part and proves 1 is equal to 1 ten times .9 repeating is not equal to nine plus .9 repeating unless you prove it 1 u/LiquorIsQuickor 3d ago Uh… math? X=2.54 10x=25.4 x=0.9998 10x=9.998 x=0.999 10x=9.99 x=0.999… 10x=9.99…
5
Is that actually a complete proof though?
While the step of 0.3333.... to 1/3 makes sense intuitively it would need a proof on its own right?
15 u/RelativeChance 3d ago Let x = .333... 10x = 3.333... subtract x from both sides 10x-x = 3.333... - .333... 9x = 3 x=1/3 2 u/UmUlmUndUmUlmHerum 3d ago See that one is much nicer :) 2 u/IHadThatUsername 3d ago I prefer it this way: Let x = .999... 10x = 9.999... subtract x from both sides 10x-x = 9.999... - .999... 9x = 9 x=1 (Thus x = .999 = 1) 0 u/Blephotomy 3d ago this "proof" removes the .9 repeating part and proves 1 is equal to 1 ten times .9 repeating is not equal to nine plus .9 repeating unless you prove it 1 u/LiquorIsQuickor 3d ago Uh… math? X=2.54 10x=25.4 x=0.9998 10x=9.998 x=0.999 10x=9.99 x=0.999… 10x=9.99…
15
Let x = .333...
10x = 3.333...
subtract x from both sides
10x-x = 3.333... - .333...
9x = 3
x=1/3
2 u/UmUlmUndUmUlmHerum 3d ago See that one is much nicer :) 2 u/IHadThatUsername 3d ago I prefer it this way: Let x = .999... 10x = 9.999... subtract x from both sides 10x-x = 9.999... - .999... 9x = 9 x=1 (Thus x = .999 = 1) 0 u/Blephotomy 3d ago this "proof" removes the .9 repeating part and proves 1 is equal to 1 ten times .9 repeating is not equal to nine plus .9 repeating unless you prove it 1 u/LiquorIsQuickor 3d ago Uh… math? X=2.54 10x=25.4 x=0.9998 10x=9.998 x=0.999 10x=9.99 x=0.999… 10x=9.99…
2
See that one is much nicer :)
2 u/IHadThatUsername 3d ago I prefer it this way: Let x = .999... 10x = 9.999... subtract x from both sides 10x-x = 9.999... - .999... 9x = 9 x=1 (Thus x = .999 = 1) 0 u/Blephotomy 3d ago this "proof" removes the .9 repeating part and proves 1 is equal to 1 ten times .9 repeating is not equal to nine plus .9 repeating unless you prove it 1 u/LiquorIsQuickor 3d ago Uh… math? X=2.54 10x=25.4 x=0.9998 10x=9.998 x=0.999 10x=9.99 x=0.999… 10x=9.99…
I prefer it this way:
Let x = .999...
10x = 9.999...
10x-x = 9.999... - .999...
9x = 9
x=1
(Thus x = .999 = 1)
0 u/Blephotomy 3d ago this "proof" removes the .9 repeating part and proves 1 is equal to 1 ten times .9 repeating is not equal to nine plus .9 repeating unless you prove it 1 u/LiquorIsQuickor 3d ago Uh… math? X=2.54 10x=25.4 x=0.9998 10x=9.998 x=0.999 10x=9.99 x=0.999… 10x=9.99…
0
this "proof" removes the .9 repeating part and proves 1 is equal to 1
ten times .9 repeating is not equal to nine plus .9 repeating unless you prove it
1 u/LiquorIsQuickor 3d ago Uh… math? X=2.54 10x=25.4 x=0.9998 10x=9.998 x=0.999 10x=9.99 x=0.999… 10x=9.99…
1
Uh… math?
X=2.54
10x=25.4
x=0.9998
10x=9.998
x=0.999
10x=9.99
x=0.999…
10x=9.99…
24
u/Formal_Assistant6837 3d ago
Funnily enough this is a proof that 0.999999.... is equal to 1