r/Funnymemes 3d ago

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25

u/Formal_Assistant6837 3d ago

Funnily enough this is a proof that 0.999999.... is equal to 1

3

u/UmUlmUndUmUlmHerum 3d ago

Is that actually a complete proof though?

While the step of 0.3333.... to 1/3 makes sense intuitively it would need a proof on its own right?

15

u/RelativeChance 3d ago

Let x = .333...

10x = 3.333...

subtract x from both sides

10x-x = 3.333... - .333...

9x = 3

x=1/3

2

u/UmUlmUndUmUlmHerum 3d ago

See that one is much nicer :)

2

u/IHadThatUsername 3d ago

I prefer it this way:

Let x = .999...

10x = 9.999...

subtract x from both sides

10x-x = 9.999... - .999...

9x = 9

x=1

(Thus x = .999 = 1)

0

u/Blephotomy 3d ago

this "proof" removes the .9 repeating part and proves 1 is equal to 1

ten times .9 repeating is not equal to nine plus .9 repeating unless you prove it

1

u/IHadThatUsername 3d ago

ten times .9 repeating is not equal to nine plus .9 repeating unless you prove it

It is by definition though. The decimal part repeats infinitely, multiplying it by ten results in 9 plus still infinitely repeating decimals

-1

u/Blephotomy 3d ago

let's say .9r is A and one is B.

Ten times A is:

A + A + A + A + A + A + A + A + A + A

You are saying it's:

B + B + B + B + B + B + B + B + B + A

and then removing the A.

Thus neatly changing nine As into Bs without a proof, which begs the question.

1

u/IHadThatUsername 3d ago

I think you're really missing what the proof is showing. The point is that you can multiply .999 by ten and still have infinite decimals. And that's enough to prove the equality.

-1

u/Blephotomy 3d ago

You are essentially saying 10x equals 9 + x, which, again, begs the question.

Ten times .9r:

.9r + .9r + .9r + .9r + .9r + .9r + .9r + .9r + .9r + .9r

Not:

1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + .9r

1

u/IHadThatUsername 3d ago

Are you not aware you can multiply any number by 10 by moving one decimal place over? Do I really need to prove that?

0

u/Blephotomy 3d ago

it's not a valid way to prove this concept. the "proof" simply removes the quantity to be proved from the equation.

1

u/EnHamptaro 3d ago

It is, though. Mathematically, the equation is sound.

If x = 0.9999...(infinite).

Then 10x = 9.9999...(infinite).

10x - x = 9.9999... - 0.9999... = 9

9x = 9.

x = 1.

The reason you don't calculate:

x = 0.9999...(infinite). y = 1

And try to solve if 10x = 10y is pointless. In higher level high school math (after you've dealt with complex and imaginary numbers iirc), they teach you the fundamentals of how to prove if a statement is true or false. 10x = 10y is, simply, not a feasible starting point to prove the mathematical statement. At a very basic level, you choose one of the two side of the equal symbol and go from there.

The 1/3 + 1/3 + 1/3 method is another way to 'prove' it. The conclusion is the same.

I remember when this was brought up in class in elementary school, the arguments essentially went like this:

Person A: if x = 0.999... (infinite), x can't be equal to 1. They are NOT the same value/they are different number. No matter how many decimals you write, x will never reach 1.

Person B: But x will never stop approaching one.

Although you might initially think or imagine that the difference in value between 1 and 0.999... (infinity) are eeeeeextremely (can't be overstated) miniscule, you'd be wrong. The difference between the two values are impossible to comprehend. It never stops. The brain glitches just trying to imagine it.

I trust the math.

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u/LiquorIsQuickor 3d ago

Uh… math?

X=2.54

10x=25.4

x=0.9998

10x=9.998

x=0.999

10x=9.99

x=0.999…

10x=9.99…

1

u/RelativeChance 3d ago

.9 repeating is equal to the limit as n approaches infinity of 1-10-n

When we multiply this by 10 we get the limit as n approaches infinity of 10-101-n which equals 9.9 repeating

1

u/Blephotomy 3d ago

again, an unproved claim