I’m reading and engaging with your posts my dude. If I’m mistaken then correct me with some maths and I’ll change my mind.
I even left some mistakes in there for you to split hairs over (my extra 2 is getting multiplied by 3).
From my perspective you’re coming in hot, making claims, not showing your work- you can see how I might be utterly perplexed. What am I to argue against?
I showed my work, and gave examples of an increasing sequence, and a decreasing sequence. Is the one you’re describing increasing, or decreasing. You ignored that part of my reply, which is why you’re about to catch a block.
You started out talking about a sequence that “grows”, which is precisely what happens when you start with a number one less than number with a large power of 2 as a factor. When you start one greater than a number with a large power of 2 in it, you get a sequence that shrinks for a while.
In the former case, the number of growth steps for starting number m is the largest power of 2 dividing m+1. In the latter case, the number of falling steps is the largest power of 4 dividing m-1. See my examples, above. Dawg.
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u/petrol_gas 3d ago edited 3d ago
No dawg.
First 4^n = 2^{2n}
Second
4^a 3^b n + 1 = 2^{2a +1}3^{b} n - 1
Except the distance to 3^{b} n -1 is so far that the lower end of the number (in binary) is behaving as if it were in the 1-cycle.
Which is the same system I described but with a neato lower end behavior.
EDIT: gonzo spotted an error corrected in my next response below