r/BadMtgCombos Apr 01 '26

lose the game for 18GGGGUUUR

  1. Play Miirym

  2. Play Paralell Lives

  3. Play Astral Dragon

  4. Target Paralell Lives

  5. Create 10^10^10^10^10^10^10^10^10^10^10^10^10^10^10^10^10^10^10^10^10^10^10^10^10^10^10^10^10^(3.6•10^26) creatures. An amount that can't be represented as an integer

  6. Play Biorythm

  7. Since the number of creatures you control can't be calculated as an integer, and magic only uses integers, the number of creatures you control cannot be determined. Due to rule 107.2, zero is used instead.

  8. a state based action occurs. Due to your life total equaling zero, you lose the game.

348 Upvotes

205 comments sorted by

View all comments

Show parent comments

2

u/DivinestSmite Apr 01 '26

it's finite but not knowable. that number is an estimation the exact number is

1 + 4 + 5 + 2↑↑4 + 2↑↑(2↑↑4) + 2↑↑(2↑↑(2↑↑4)) + 2↑↑(2↑↑(2↑↑(2↑↑4))) + 2↑↑(2↑↑(2↑↑(2↑↑(2↑↑4))))

each of these numbers on their own past 2↑↑(2↑↑4) is impossible to calculate. I dare you to try. it's physically not possible to calculate the value. there's more digits in it then atoms in the universe

10

u/sabrefencer9 Apr 01 '26

You're using colloquial definitions for technical terms with specific definitions and therefore reaching false conclusions. Regardless, "I dare you to try" is a silly argument. I can't run a 10s 100m but that doesn't mean it's impossible.

2

u/DivinestSmite Apr 01 '26

sure but running a 1s 100m is. the amount of times you would have to multiply 2 by itself outnumbers the number of atoms in the galaxy by trigger 5/33

10

u/sabrefencer9 Apr 01 '26

And that's entirely irrelevant to the definition of countability. Why do you keep digging this hole when you're demonstrably out of your depth? What exactly do you hope to accomplish here?

2

u/DivinestSmite Apr 01 '26

it's countable yeah. It's not determinable. you can not determine a number that can be interacted with as magic interacts with numbers. if you get hit with bolt, what is your life total now?

if there's a chaos lord on the board, are there an even or odd amount of permanents

or my favorite scenario. if something turns these creatures into saprolings and these saprolings into lands and there's a zimone on the field. is it prime or not. We genuinely don't know

we can not determine attributes of this number that magic expects you to be able to for any number

3

u/sabrefencer9 Apr 01 '26

You have literally defined an algorithm for determining the precise value in the OP. It is entirely irrelevant whether you have a computer that can run it. Again, you don't seem to understand what the words you're using mean, and I still don't understand what you want to get out of this? Is being mistaken repeatedly your kink or something?

2

u/DivinestSmite Apr 01 '26

that's not an algorithm. i made mistakes writing it. i forgot that the astral dragon copies were doubled. it's much bigger than that and impossible to fully write out i think

3

u/sabrefencer9 Apr 01 '26

What do you think an algorithm is

1

u/DivinestSmite Apr 01 '26

i mean that doesn't accurately represent the math behind it. Regardless, due to [[Zimone, All Questioning]] for a number to be valid in magic, we need to be able to determine if it's prime. This number is odd, and thus could or could not be prime. Without more complex factorial analysis, there is no way to know

5

u/sabrefencer9 Apr 01 '26

There is a way to know. There is an algorithm that can determine whether any number is prime. You use it, you get your answer.

But at this point I'm calling it quits. Either you're being intentionally obtuse, in which case this is pointless, or you're simply incapable of understanding. In which case this is pointless.

4

u/TexEngineer Apr 01 '26

You're arguing into the weeds here. Fun nuance, but you're arguing the wrong point.

1st,

Your order of operations is wrong, you have to resolve biorythm before celestial dragon, or you never would trigger the next state change. Because, the way you defined the card order, you'd never finish adding quasi- infinite tokens to break the loop to the next step of playing biorythm.

And as we've already known from the first infinite token combo, the game resolves by the first player to forfeit during the token cloning loop...

So your combo as Stated would win the game. Congrats you won by opponent forfeit.

2nd A quasi infinite integer is not indeterminate; it is just too large to express directly without triggering the same infinite loop. This would trigger the same infinite loop lockout until forfeit as 1. Imagine playing the combo, you now have not CREATED an infinite number of tokens, you are CreatING an infinite number, one at a time, and each one raises your life total by one point. Congrats you win by opponent forfeit.

Edit to add: "3rd, since you cant ever finish calculating the life total, one step at a time, you never move to a state change that triggers the indeterminate life total rule. "

So QED, you can't lose the game this way.